Optimal. Leaf size=171 \[ -\frac{\left (16 a^2 b c+3 a^3 d+12 a b^2 d+4 b^3 c\right ) \cos (e+f x)}{6 f}-\frac{b \left (6 a^2 d+20 a b c+9 b^2 d\right ) \sin (e+f x) \cos (e+f x)}{24 f}+\frac{1}{8} x \left (12 a^2 b d+8 a^3 c+12 a b^2 c+3 b^3 d\right )-\frac{(3 a d+4 b c) \cos (e+f x) (a+b \sin (e+f x))^2}{12 f}-\frac{d \cos (e+f x) (a+b \sin (e+f x))^3}{4 f} \]
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Rubi [A] time = 0.197485, antiderivative size = 171, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.087, Rules used = {2753, 2734} \[ -\frac{\left (16 a^2 b c+3 a^3 d+12 a b^2 d+4 b^3 c\right ) \cos (e+f x)}{6 f}-\frac{b \left (6 a^2 d+20 a b c+9 b^2 d\right ) \sin (e+f x) \cos (e+f x)}{24 f}+\frac{1}{8} x \left (12 a^2 b d+8 a^3 c+12 a b^2 c+3 b^3 d\right )-\frac{(3 a d+4 b c) \cos (e+f x) (a+b \sin (e+f x))^2}{12 f}-\frac{d \cos (e+f x) (a+b \sin (e+f x))^3}{4 f} \]
Antiderivative was successfully verified.
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Rule 2753
Rule 2734
Rubi steps
\begin{align*} \int (a+b \sin (e+f x))^3 (c+d \sin (e+f x)) \, dx &=-\frac{d \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}+\frac{1}{4} \int (a+b \sin (e+f x))^2 (4 a c+3 b d+(4 b c+3 a d) \sin (e+f x)) \, dx\\ &=-\frac{(4 b c+3 a d) \cos (e+f x) (a+b \sin (e+f x))^2}{12 f}-\frac{d \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}+\frac{1}{12} \int (a+b \sin (e+f x)) \left (12 a^2 c+8 b^2 c+15 a b d+\left (20 a b c+6 a^2 d+9 b^2 d\right ) \sin (e+f x)\right ) \, dx\\ &=\frac{1}{8} \left (8 a^3 c+12 a b^2 c+12 a^2 b d+3 b^3 d\right ) x-\frac{\left (16 a^2 b c+4 b^3 c+3 a^3 d+12 a b^2 d\right ) \cos (e+f x)}{6 f}-\frac{b \left (20 a b c+6 a^2 d+9 b^2 d\right ) \cos (e+f x) \sin (e+f x)}{24 f}-\frac{(4 b c+3 a d) \cos (e+f x) (a+b \sin (e+f x))^2}{12 f}-\frac{d \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}\\ \end{align*}
Mathematica [A] time = 0.645167, size = 142, normalized size = 0.83 \[ \frac{3 \left (4 (e+f x) \left (12 a^2 b d+8 a^3 c+12 a b^2 c+3 b^3 d\right )-8 b \left (3 a^2 d+3 a b c+b^2 d\right ) \sin (2 (e+f x))+b^3 d \sin (4 (e+f x))\right )-24 \left (12 a^2 b c+4 a^3 d+9 a b^2 d+3 b^3 c\right ) \cos (e+f x)+8 b^2 (3 a d+b c) \cos (3 (e+f x))}{96 f} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.029, size = 182, normalized size = 1.1 \begin{align*}{\frac{1}{f} \left ({a}^{3}c \left ( fx+e \right ) -{a}^{3}d\cos \left ( fx+e \right ) -3\,{a}^{2}bc\cos \left ( fx+e \right ) +3\,{a}^{2}bd \left ( -1/2\,\sin \left ( fx+e \right ) \cos \left ( fx+e \right ) +1/2\,fx+e/2 \right ) +3\,a{b}^{2}c \left ( -1/2\,\sin \left ( fx+e \right ) \cos \left ( fx+e \right ) +1/2\,fx+e/2 \right ) -a{b}^{2}d \left ( 2+ \left ( \sin \left ( fx+e \right ) \right ) ^{2} \right ) \cos \left ( fx+e \right ) -{\frac{{b}^{3}c \left ( 2+ \left ( \sin \left ( fx+e \right ) \right ) ^{2} \right ) \cos \left ( fx+e \right ) }{3}}+{b}^{3}d \left ( -{\frac{\cos \left ( fx+e \right ) }{4} \left ( \left ( \sin \left ( fx+e \right ) \right ) ^{3}+{\frac{3\,\sin \left ( fx+e \right ) }{2}} \right ) }+{\frac{3\,fx}{8}}+{\frac{3\,e}{8}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.08413, size = 236, normalized size = 1.38 \begin{align*} \frac{96 \,{\left (f x + e\right )} a^{3} c + 72 \,{\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a b^{2} c + 32 \,{\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} b^{3} c + 72 \,{\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a^{2} b d + 96 \,{\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} a b^{2} d + 3 \,{\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} b^{3} d - 288 \, a^{2} b c \cos \left (f x + e\right ) - 96 \, a^{3} d \cos \left (f x + e\right )}{96 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.72184, size = 340, normalized size = 1.99 \begin{align*} \frac{8 \,{\left (b^{3} c + 3 \, a b^{2} d\right )} \cos \left (f x + e\right )^{3} + 3 \,{\left (4 \,{\left (2 \, a^{3} + 3 \, a b^{2}\right )} c + 3 \,{\left (4 \, a^{2} b + b^{3}\right )} d\right )} f x - 24 \,{\left ({\left (3 \, a^{2} b + b^{3}\right )} c +{\left (a^{3} + 3 \, a b^{2}\right )} d\right )} \cos \left (f x + e\right ) + 3 \,{\left (2 \, b^{3} d \cos \left (f x + e\right )^{3} -{\left (12 \, a b^{2} c +{\left (12 \, a^{2} b + 5 \, b^{3}\right )} d\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{24 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 1.73381, size = 386, normalized size = 2.26 \begin{align*} \begin{cases} a^{3} c x - \frac{a^{3} d \cos{\left (e + f x \right )}}{f} - \frac{3 a^{2} b c \cos{\left (e + f x \right )}}{f} + \frac{3 a^{2} b d x \sin ^{2}{\left (e + f x \right )}}{2} + \frac{3 a^{2} b d x \cos ^{2}{\left (e + f x \right )}}{2} - \frac{3 a^{2} b d \sin{\left (e + f x \right )} \cos{\left (e + f x \right )}}{2 f} + \frac{3 a b^{2} c x \sin ^{2}{\left (e + f x \right )}}{2} + \frac{3 a b^{2} c x \cos ^{2}{\left (e + f x \right )}}{2} - \frac{3 a b^{2} c \sin{\left (e + f x \right )} \cos{\left (e + f x \right )}}{2 f} - \frac{3 a b^{2} d \sin ^{2}{\left (e + f x \right )} \cos{\left (e + f x \right )}}{f} - \frac{2 a b^{2} d \cos ^{3}{\left (e + f x \right )}}{f} - \frac{b^{3} c \sin ^{2}{\left (e + f x \right )} \cos{\left (e + f x \right )}}{f} - \frac{2 b^{3} c \cos ^{3}{\left (e + f x \right )}}{3 f} + \frac{3 b^{3} d x \sin ^{4}{\left (e + f x \right )}}{8} + \frac{3 b^{3} d x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{4} + \frac{3 b^{3} d x \cos ^{4}{\left (e + f x \right )}}{8} - \frac{5 b^{3} d \sin ^{3}{\left (e + f x \right )} \cos{\left (e + f x \right )}}{8 f} - \frac{3 b^{3} d \sin{\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{8 f} & \text{for}\: f \neq 0 \\x \left (a + b \sin{\left (e \right )}\right )^{3} \left (c + d \sin{\left (e \right )}\right ) & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.39458, size = 205, normalized size = 1.2 \begin{align*} \frac{b^{3} d \sin \left (4 \, f x + 4 \, e\right )}{32 \, f} + \frac{1}{8} \,{\left (8 \, a^{3} c + 12 \, a b^{2} c + 12 \, a^{2} b d + 3 \, b^{3} d\right )} x + \frac{{\left (b^{3} c + 3 \, a b^{2} d\right )} \cos \left (3 \, f x + 3 \, e\right )}{12 \, f} - \frac{{\left (12 \, a^{2} b c + 3 \, b^{3} c + 4 \, a^{3} d + 9 \, a b^{2} d\right )} \cos \left (f x + e\right )}{4 \, f} - \frac{{\left (3 \, a b^{2} c + 3 \, a^{2} b d + b^{3} d\right )} \sin \left (2 \, f x + 2 \, e\right )}{4 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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